Compose a 1250 words assignment on natural environment of escherichia coli. Needs to be plagiarism free!

Compose a 1250 words assignment on natural environment of escherichia coli. Needs to be plagiarism free! E.coli also causes bloody and non-bloody diarrhoea and is transmitted via the faecal-oral route (thus it is important to wash hands and foods very well in addition to proper handling and disposal of sewage, faeces etc). E.coli and other Enterobacteriaceae are the commonest pathogens in existence, alongside the Staphylococci and Streptococci.

E.coli is regarded as part of the normal flora of the animal and human body. It is usually present in the colon (large intestine) i.e. its natural habitat is mainly the gastrointestinal tract. By virtue of its enteric location, E.coli can be present in very high concentrations (reaching levels up to 108 per gram) in human faeces.

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E.coli is a facultative anaerobe depending on the prevailing circumstances i.e. E.coli can make use of oxygen when it is present or generate energy by anaerobiosis in an oxygen-poor environment. In another word, E.coli can metabolize nutrients by respiration or fermentation. E.coli also carries out the fermentation of quite a number of carbohydrates. It has been firmed that E.coli grows well on meat extract medium without adding sodium chloride and also reproduce well on MacConkey’s agar. E.coli also ferments lactose rapidly. In fermentation, a substance (preferable an organic compound) will accept the hydrogen ion being donated as against respiration in which oxygen is the hydrogen acceptor.

It was hypothesized that E.coli will produce growth with a particular pattern which can be shown as a growth curse when measured amounts of bacteria inoculations are added to the fresh liquid media (when can be MacConkey’s agar) L. Broth which was used in this experiments.

1ml of E.coli in inoculums from a saturated culture was added to a fresh sample of 50ml of L-Broth. The L-Broth is expected to produce a unique and particularly nutrient-rich environment that will encourage the growth of E.coli.&nbsp.&nbsp.

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